Please visit VK2TIP's Book Shelf. My personal recommendations, thanks.
Friday, 29-Jun-2018 03:08:08 PDT
•NEW! ‣ - Amazon Electronic Component Packs. Check out the Amazon Electronic Component Packs page.
A meter shunt is a useful means of extending the current range of an ammeter. As current divides between two resistors in parallel it is possible to increase the range of a DC microammeter or milliammeter by paralleling an additional resistance with the inherent DC resistance of the meter itself. This is called a meter shunt.
It would prove helpful in considering meter shunts to consider the topic of meters first if you haven't already done so.
Typical ammeter ranges available to hams and electronic hobbyists are usually the 100 micro-amperes and 0 - 1 milli-ampere types. Obviously there are other ranges, especially when we consider surplus sales of meters.
Let's assume we have a typical 0 - 1 milliampere millammeter and want to extend it's useful range to record current up to 5 amps for a power supply project.
In figure 1 is a typical panel milliammeter of the MU45 type (45mm).
Figure 1 - a 0 to 1 mA ammeter requiring a meter shunt
So how do we make a meter shunt to go from 0 - 1 mA all the way out to 5A? Consider the schematic in figure 2 which gives you some idea on what we're about.
Figure 2 - schematic of a 0 to 1 mA ammeter with a meter shunt
The formula to determine the shunt resistance is:
R shunt = R meter / (n - 1)
Where R shunt is our meter shunt resistance, R meter is the inherent meter resistance and "n" is the multiplier. In our example the multiplier "n" is 5A divided by 1 mA or 5 / 0.001 which of course equals 5000. So (n - 1) must be 5,000 - 1 = 4,999.
For this exercise we will assume our internal meter resistance (R meter) was accurately measured as 58 ohms.
Now substituting all those values into our formula we get a meter shunt resistance of:
R shunt = 58 / (5,000 - 1) = 0.0116 ohms
This meter shunt resistance must be capable of safely carrying our anticipated maximum current, in this case 5 amperes.
A fairly useful guide for current carrying capacity for ordinary copper wire of the type generally available to us is 250 circular mils per ampere. Mils in this context are thousandths of an inch and circular mils are simply the diameter of the wire in thousandths of an inch squared. So 5 amperes would require something in the region of 1,250 circ mils, the square root of which is about 35 mils diameter or about 0.9 mm.
Allowing a factor of safety we could look at AWG #19 which is described in wire tables as being 0.912 mm dia, 35.9 mils dia, 1288 circ. mils, and has a resistance of 8.21 ohms per 1,000' (305 metres) at 25 degrees centigrade.
It follows if the resistance is 8.21 ohms / 1000' then to obtain the required length of #19 copper wire we use the formula:
Length (in feet) = R shunt / [R wire / 1000]
Or length = 0.0116 / [8.21 / 1000] = 1.4129' ( always convert to metric by multiplying by 305 ) In this case in metric, we get 431 mm of #19 gauge copper wire. This length of wire should be wound on a suitably convenient form to withstand the heat generated and preferably spaced one turn apart (especially if you didn't use enamelled wire).
Be aware those figures are only likely to be valid at 25 C or 77 F.
Professionals in the instrument field would of course use other materials. If you have access to an accurate milli-ohmeter consider using wire salvaged from electric heating appliances such as toasters, jugs or radiators. Bear in mind such wire has different temperature properties i.e., as it heats up the wire resistance can vary quite significantly.
To give me feedback, comments or suggestions use this friendly form.
NEW! - How to link directly to this page
Want to create a page link to me from your site? It couldn't be easier. No HTML knowledge required; even the technophobes can do it. All you need to do is copy and paste, the following code. All links are greatly appreciated; I sincerely thank you for your support.
Copy and paste the following code for a text link:
and it should appear like this:
href="https://www.electronics-tutorials.com/test-equip/meter-shunt.htm" target="_top">visit VK2TIP's Meter Shunt Page</a>
visit VK2TIP's Meter Shunt Page
and it should appear like this:
If you are involved in electronics then consider joining our "electronics Questions and Answers" news group to ask your question there as well as sharing your thorny questions and answers. Help out your colleagues!.
The absolute fastest way to get your question answered and yes, I DO read most posts.
This is a mutual help group with a very professional air about it. I've learn't things. It is an excellent learning resource for lurkers as well as active contributors.
Join our "electronics discussion group"
Looking for more? Visit my site map page:
This site is hosted at Press Wizards for better value.
the author Ian C. Purdie, VK2TIP of www.electronics-tutorials.com asserts the moral right to
be identified as the author of this web site and all contents herein. Copyright © 2000 - 2001, all rights reserved. See copying and links.
These electronic tutorials are provided for individual private use and the author assumes no liability whatsoever for the application, use, misuse, of any of these projects or electronics tutorials that may result in the direct or indirect damage or loss that comes from these projects or tutorials. All materials are provided for free private and public use.
Commercial use prohibited without prior written permission from www.electronics-tutorials.com.
Copyright © 2000 - 2001, all rights reserved. URL - https://www.electronics-tutorials.com/test-equip/meter-shunt.htm
Updated 13th January, 2001